上 y=x^2-4x-5 in factored form 314307

Solving Quadratic Equations

Solving Quadratic Equations

Q The polynomial f (x) = 5x4 2x3 2x − 7 can have, at most, how many solutions?(Carefulpay attention to multiplicity) Q What does multiplicity of a zero mean?

Y=x^2-4x-5 in factored form

Y=x^2-4x-5 in factored form-Click here 👆 to get an answer to your question ️ factored form x^2 4x 21? 45 Express each equation in the specified form a y = (x – 3)² 25 in standard form B y = 2 (x – 7) (x 3) in standard form C y = 2x² 28x – 26 in factored form D y = 9x² 72x 81 in vertex form

Graphs Of Polynomial Functions Algebra And Trigonometry

Graphs Of Polynomial Functions Algebra And Trigonometry

To find the xintercept (s), substitute in 0 0 for y y and solve for x x 0 = x 2 4 x − 5 0 = x 2 4 x 5 Solve the equation Tap for more steps Rewrite the equation as x 2 4 x − 5 = 0 x 2 4 x 5 = 0 x 2 4 x − 5 = 0 x 2 4 x 5 = 0 Factor x 2 4 x − 5 x 2 4 x 5 using the AC method In this we split the middle term into two terms making the polynomial easily factorizable The spiting should be done such that the product of the two middle terms should be equal to the product of coefficients of the x2 and constant term y = 4x2 11x 6 Terms would be 8 and 3 as 8 × 3 = 4 × 6 y = 4x2 8x 3x 6 or y = 4x2 3x 8x 61 See answer mamilongarms is waiting for your help Add your answer and earn points rejkjavik rejkjavik we are given x^24x5 we can use formula x^2(ab)xab=(xa)(xb) so, we have ab=4 ab=5 now, we can solve for a and b

Question I need help with putting y=x^43x^34x^2 in factored form And write a polynomial function in standard form with the given zeros 2,Q Which of the following could be the equation of this graph in factored form?What is the factored form of x^2 4x 5?

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Find the Vertex Form y=x^24x Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola Substitute the values of and into the formula Simplify the right side Tap for more steps Cancel the common factor of andFactor 4x^21 4x2 − 1 4 x 2 1 Rewrite 4x2 4 x 2 as (2x)2 ( 2 x) 2 (2x)2 − 1 ( 2 x) 2 1 Rewrite 1 1 as 12 1 2 (2x)2 − 12 ( 2 x) 2 1 2 Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (ab)(a−b) a 2 b 2 = ( a b) ( a b) where a = 2x a = 2 x and b = 1 b = 1 (2x1)(2x−1

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